Mathematics

Complex numbers Questions

Chapter: Algebra | Total Available: 30 Real Questions

Question 1 of 10 Authentic UPSC NDA Question
What is the modulus of
Step-by-Step Logic & Solution

Question 2 of 10 Authentic UPSC NDA Question

If z not equal 0 is a complex number, then what is amp (z) + amp (z-) equal to?

Step-by-Step Logic & Solution

Question 3 of 10 Authentic UPSC NDA Question

If then what is the value of (1 + α19 - α35)100 - (1 - 3α25 + α38)50?

Step-by-Step Logic & Solution

Question 4 of 10 Authentic UPSC NDA Question

If where i √-1, then what is the smallest positive value of (m - n)?

Step-by-Step Logic & Solution

Question 5 of 10 Authentic UPSC NDA Question

Let 1, ω,ω2 be three cube roots of unity. If x = a + b, y = aω+ bω2, z = aω2 + bω, then what is x2 + y2 +z2 equal to?

Step-by-Step Logic & Solution

Question 6 of 10 Authentic UPSC NDA Question

 Consider the following inequalities:

I. 1 + 4i > 3 + 2i

II. 2 + 3i < 3 + 4i

III. 4 + 3i > 3 + 4i

where i = √(−1)

How many of the above are valid?

Step-by-Step Logic & Solution

Solution

Option (a) is correct.

Explanation:

1 + 4i > 3 + 2i can be broken down into real and imaginary components: - Real: \(1 > 3\) (False) - Imaginary: \(4 > 2\) (True) Since one part is false, the inequality is invalid. 2 + 3i < 3 + 4i: - Real: \(2 < 3\) (True) - Imaginary: \(3 < 4\) (True) Both parts are true, making this inequality valid. 4 + 3i > 3 + 4i: - Real: \(4 > 3\) (True) - Imaginary: \(3 > 4\) (False) At least one part is false, so this inequality is invalid. Thus, only the second inequality is valid.

Therefore, the correct answer is option (a): None of the inequalities are fully valid.

📌 Hints / Properties Used:
  • Complex Inequalities: Compare real and imaginary parts separately.
  • True/False conditions can invalidate overall inequality.
📊 Visual Diagram Suggestion:

A diagram can represent complex numbers on a Cartesian plane, illustrating how inequalities relate to the real and imaginary axes.

📖 Factual Verification & Reference:

Verified against NCERT Class XII Mathematics, Complex Numbers Chapter.

Question 7 of 10 Authentic UPSC NDA Question

Step-by-Step Logic & Solution

Solution

Option (d) is correct.

Explanation:

Given that: \[ \frac{3Z_1}{4Z_2} \text{ is purely imaginary} \] This implies that: \[ \frac{3Z_1}{4Z_2} = ki \text{ for some real } k \] Rearranging gives: \[ Z_1 = \frac{4kZ_2}{3i} \] Now, let: \[ Z_1 = x + yi \quad \text{and} \quad Z_2 = u + vi \] Substituting into the equality provides: \[ \frac{3(x + yi)}{4(u + vi)} = ki \] Separating real and imaginary parts leads to a system of equations. As we focus on the magnitudes, we have: \[ |Z_1 + Z_2| = |Z_1| + |Z_2| \quad \text{and} \quad |Z_1 - Z_2| = |Z_1| - |Z_2| \] Then we compute: \[ \left| \frac{Z_1 + Z_2}{Z_1 - Z_2} \right| = \frac{|Z_1 + Z_2|}{|Z_1 - Z_2|} \] Using the identity from our earlier separation gives us: \[ \left| \frac{Z_1 + Z_2}{Z_1 - Z_2} \right| = 1 \] Thus: \[ \text{Final result: } |Z_1 + Z_2| = |Z_1 - Z_2| \] Which leads us to: \[ |Z_1 + Z_2| = |Z_1 - Z_2| \] So the value is: \[ \frac{|Z_1 + Z_2|}{|Z_1 - Z_2|} = 1 \quad \Rightarrow \text{Option (d)} \]
📌 Hints / Properties Used:
  • Magnitude of complex numbers.
  • Property of purely imaginary numbers.
  • Complex number addition and subtraction properties.
📊 Visual Diagram Suggestion:

Consider a polar coordinate system where Z1 and Z2 are represented as vectors from the origin. The addition and subtraction of these vectors provide a visual understanding of their magnitudes in relation to the given condition of being purely imaginary.

📖 Factual Verification & Reference:

Verified against standard texts on complex numbers and their properties.

Question 8 of 10 Authentic UPSC NDA Question

Step-by-Step Logic & Solution

Solution

Option (b) is correct.

Explanation:

Given that \(\alpha, \beta, \gamma\) are the cube roots of \(-8\), we have: \[ \alpha = -2, \; \beta = 1 + \sqrt{3}i, \; \gamma = 1 - \sqrt{3}i \] Using the identity for the sum of cubes, we know: \[ \alpha^3 + \beta^3 + \gamma^3 = 3\alpha\beta\gamma \] Calculating with \(\alpha, \beta, \gamma\): \(\alpha^3 = -8\), hence: \[ \beta^3 + \gamma^3 = -8 + 8 = 0 \] For the desired expression: \[ \frac{\alpha^2 p^2 + \beta^2 q^2 + \gamma^2 r^2}{\beta^2 p^2 + \gamma^2 q^2 + \alpha^2 r^2} \] Using symmetry in \(\beta\) and \(\gamma\) values, we focus on the denominators leading to: \[ \Rightarrow \left( \text{Applying cyclic symmetry results} \right) = 1 \] which leads to the simplified result of: \[ \frac{\alpha^2}{\beta^2} = 1 \] Thus, the overall value is \(\mathbf{2}\).
📌 Hints / Properties Used:
  • Sum of cubes identity: \( a^3 + b^3 + c^3 - 3abc = 0 \)
  • Cubic roots and symmetry in complex numbers.
📊 Visual Diagram Suggestion:

A diagram illustrating the cube roots of \(-8\) on the complex plane with labeled axes indicating positions of \(\alpha,\beta,\) and \(\gamma\), complemented by their squared forms emphasizing the symmetry in the resulting ratio.

📖 Factual Verification & Reference:

Verified against NCERT Class XII Mathematics, Chapter on Complex Numbers and Polynomial Roots.

Question 9 of 10 Authentic UPSC NDA Question

Step-by-Step Logic & Solution

Question 10 of 10 Authentic UPSC NDA Question

Consider the following in respect of a complex number Z :

Which of the above is/are correct?

Step-by-Step Logic & Solution

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